Shapes in Coordinates

Back

Loading concept...

🗺️ Shapes in Coordinates: Your Treasure Map to Geometry!

Imagine you have a magical treasure map with a grid on it. Every treasure, every landmark, every path can be found using two numbers: how far right (x) and how far up (y). This is Coordinate Geometry — using numbers to describe shapes!

Today, we’ll learn how to find treasure (triangles, circles, special points) using just coordinates. Ready? Let’s go!


🔺 Area of a Triangle Using Coordinates

The Story

Three pirates bury treasure at three spots on their map. How much ground does their triangle cover?

The Magic Formula

If three points are A(x₁, y₁), B(x₂, y₂), and C(x₃, y₃):

Area = ½ |x₁(y₂ - y₃) + x₂(y₃ - y₁) + x₃(y₁ - y₂)|

The | | means “always positive” — area can’t be negative!

Example

Points: A(0, 0), B(4, 0), C(2, 3)

Area = ½ |0(0-3) + 4(3-0) + 2(0-0)|
     = ½ |0 + 12 + 0|
     = ½ × 12
     = 6 square units

Why It Works

Think of it like measuring a pizza slice. The formula counts how much space is inside by using the coordinates as measurements!


➡️ Collinearity Condition

The Story

Three friends standing in a park. Are they in a straight line or forming a triangle?

The Rule

Three points are collinear (on the same line) if the area of the triangle they form is ZERO.

If x₁(y₂ - y₃) + x₂(y₃ - y₁) + x₃(y₁ - y₂) = 0, points are collinear!

Example

Are A(1, 2), B(3, 4), and C(5, 6) collinear?

= 1(4-6) + 3(6-2) + 5(2-4)
= 1(-2) + 3(4) + 5(-2)
= -2 + 12 - 10
= 0 ✓ Yes! They're on the same line!

Think of it This Way

If three points form a triangle with NO area, they must be squished into a line!


⭕ Circumcenter Coordinates

The Story

Imagine three friends want to stand in a circle, all the same distance from a special center point. That center is the circumcenter!

What is Circumcenter?

  • The center of a circle that passes through ALL THREE vertices of a triangle
  • It’s equidistant (same distance) from all three corners

Finding the Circumcenter

The circumcenter is where the perpendicular bisectors of the sides meet.

For a triangle with vertices A(x₁, y₁), B(x₂, y₂), C(x₃, y₃):

graph TD A["Find midpoint of AB"] --> D["Draw line perpendicular to AB at midpoint"] B["Find midpoint of BC"] --> E["Draw line perpendicular to BC at midpoint"] D --> F["Where lines cross = Circumcenter!"] E --> F

Example

For a right triangle at A(0, 0), B(4, 0), C(0, 3):

The circumcenter is at the midpoint of the hypotenuse!

  • Hypotenuse BC: midpoint = ((4+0)/2, (0+3)/2) = (2, 1.5)

That’s the circumcenter! The circle with center (2, 1.5) passes through all three points.


🎯 Orthocenter Coordinates

The Story

Drop a perpendicular line from each corner of a triangle to the opposite side. Where do all three lines meet? That’s the orthocenter!

What is Orthocenter?

  • The point where all three altitudes meet
  • An altitude = a line from a vertex perpendicular to the opposite side

Key Facts

Triangle Type Orthocenter Location
Acute triangle Inside the triangle
Right triangle At the right-angle vertex
Obtuse triangle Outside the triangle

Example

For a right triangle at A(0, 0), B(4, 0), C(0, 3):

The right angle is at A(0, 0). Orthocenter = A(0, 0)

For right triangles, the orthocenter is always at the corner with the 90° angle!

Finding Orthocenter (General Method)

  1. Find the equation of altitude from vertex A
  2. Find the equation of altitude from vertex B
  3. Solve both equations to find intersection point

⚪ Equation of a Circle

The Story

A circle is like a fence around a tree. Every point on the fence is the same distance from the tree (center).

Standard Form

A circle with center (h, k) and radius r:

(x - h)² + (y - k)² = r²

Breaking It Down

  • (h, k) = where the center is
  • r = how big the circle is (radius)
  • Every point (x, y) on the circle satisfies this equation

Example

Circle with center (3, 2) and radius 5:

(x - 3)² + (y - 2)² = 25

Let’s check: Is point (6, 6) on this circle?

(6-3)² + (6-2)² = 9 + 16 = 25 ✓ Yes!

Special Case: Center at Origin

If center is (0, 0):

x² + y² = r²


🔍 Circle from Equation

The Story

Someone gives you a messy equation. Can you figure out where the circle is and how big it is?

General Form

x² + y² + Dx + Ey + F = 0

Converting to Standard Form

Use completing the square!

Example

Find center and radius: x² + y² - 6x + 4y - 12 = 0

Step 1: Group x terms and y terms

(x² - 6x) + (y² + 4y) = 12

Step 2: Complete the square

  • For x: take -6, halve it (-3), square it (9)
  • For y: take 4, halve it (2), square it (4)
(x² - 6x + 9) + (y² + 4y + 4) = 12 + 9 + 4

Step 3: Factor

(x - 3)² + (y + 2)² = 25

Answer: Center = (3, -2), Radius = 5

Quick Reference

General Form Find Center Find Radius
x² + y² + Dx + Ey + F = 0 (-D/2, -E/2) √(D²/4 + E²/4 - F)

📐 Coordinate Proofs

The Story

Instead of using rulers and protractors, we can prove things about shapes using coordinates!

The Strategy

  1. Place the shape on a coordinate grid cleverly
  2. Assign coordinates to vertices
  3. Calculate using formulas
  4. Prove what you need!

Common Placements

Shape Smart Placement
Rectangle One corner at origin, sides along axes
Triangle One side along x-axis
Square Center at origin

Example Proof: Diagonals of a Rectangle Bisect Each Other

Setup: Rectangle ABCD

  • A = (0, 0)
  • B = (a, 0)
  • C = (a, b)
  • D = (0, b)

Prove: Diagonals AC and BD have the same midpoint

Diagonal AC: from (0, 0) to (a, b)

  • Midpoint = ((0+a)/2, (0+b)/2) = (a/2, b/2)

Diagonal BD: from (a, 0) to (0, b)

  • Midpoint = ((a+0)/2, (0+b)/2) = (a/2, b/2)

Same point! ✓ Proved!

graph TD A["Step 1: Place shape on grid"] --> B["Step 2: Assign coordinates"] B --> C["Step 3: Use distance/midpoint formulas"] C --> D["Step 4: Show equality or relationship"] D --> E["Proof complete! 🎉"]

Another Example: Midpoint of Hypotenuse

Prove: The midpoint of the hypotenuse of a right triangle is equidistant from all three vertices.

Setup: Right triangle

  • A = (0, 0) — right angle
  • B = (2a, 0)
  • C = (0, 2b)

Midpoint M of hypotenuse BC:

  • M = ((2a+0)/2, (0+2b)/2) = (a, b)

Distances:

  • MA = √(a² + b²)
  • MB = √((a-2a)² + (b-0)²) = √(a² + b²)
  • MC = √((a-0)² + (b-2b)²) = √(a² + b²)

All equal! ✓ The midpoint is equidistant from all vertices!


🎯 Summary: Your Coordinate Geometry Toolkit

Tool What It Does Key Formula
Triangle Area Find space inside ½|x₁(y₂-y₃) + x₂(y₃-y₁) + x₃(y₁-y₂)|
Collinearity Check if points are in line Area = 0
Circumcenter Circle center through vertices Perpendicular bisector intersection
Orthocenter Where altitudes meet Altitude intersection
Circle Equation Describe a circle (x-h)² + (y-k)² = r²
Circle from Equation Find center & radius Complete the square
Coordinate Proofs Prove properties Place → Assign → Calculate → Prove

🌟 You Did It!

You’ve learned to:

  • ✅ Calculate triangle areas with coordinates
  • ✅ Check if points are collinear
  • ✅ Find circumcenters and orthocenters
  • ✅ Write and read circle equations
  • ✅ Prove geometric facts with coordinates

Coordinate geometry turns shapes into numbers and numbers into discoveries. You now have the map — go find your treasure! 🗺️✨

Loading story...

Story - Premium Content

Please sign in to view this story and start learning.

Upgrade to Premium to unlock full access to all stories.

Stay Tuned!

Story is coming soon.

Story Preview

Story - Premium Content

Please sign in to view this concept and start learning.

Upgrade to Premium to unlock full access to all content.